Inductor Energy Calculator - Magnetic Energy Solver

Use this inductor energy calculator to solve E = 1/2 L I^2 for any coil with H, mH, µH, nH inductance and A, mA or µA current with auto J, mJ, µJ output.

Updated: June 25, 2026 • Free Tool

Inductor Energy Calculator

Self-inductance of the coil. Converted from the selected prefix to henries before E = 1/2 L I^2.

Prefix applied to the inductance before the formula runs.

Steady current flowing through the coil. Converted from the selected prefix to amperes before E = 1/2 L I^2.

Prefix applied to the current before the formula runs.

Used only when Solve For is Current or Inductance. Enter the magnetic energy you want the coil to store.

Prefix applied to the target energy value before the reverse solve runs.

Pick the unknown: stored energy, current needed to hit a target energy, or inductance needed to hit a target energy.

Results

Stored Magnetic Energy
0
Inductance 0H
Current 0A
Current Squared (I^2) 0A^2

What Is Inductor Energy Calculator?

An inductor energy calculator is a fast way to solve E = 1/2 L I^2, the textbook equation for the magnetic energy stored in a coil of inductance L carrying a steady current I. Drop in an inductance in henries, millihenries, microhenries, or nanohenries and a current in amperes, milliamperes, or microamperes, and the tool returns the stored energy in joules with an auto-prefixed nJ, µJ, mJ, or J display. Engineers size DC inductors with it, students confirm homework answers, and hobbyists sanity-check flyback transformer designs.

  • DC inductor sizing: Estimate magnetic energy at the operating current to pick a saturation rating.
  • Switching supply design: Check joules a buck, boost, or flyback inductor carries per cycle before sizing the snubber.
  • LC tank circuit analysis: Pair magnetic energy with capacitor energy to confirm resonance in RF or audio filters.
  • Physics homework: Confirm a textbook answer for the magnetic energy of a solenoid given L and I.

The same formula works for any coil geometry because inductance already absorbs coil length, area, and turn count. Solenoids, toroids, and air-core chokes are all valid inputs as long as you know their inductance in henries.

Real coils include series resistance, so some supply energy dissipates as heat instead of being stored in the magnetic field. The tool assumes an ideal, lossless inductor and reports only the field energy term from E = 1/2 L I^2.

When the same coil is used in an AC circuit, the inductive reactance calculator gives the frequency-domain impedance XL = 2π f L from the same inductance value, so the two tools cover the steady-state DC energy and the AC reactance of the same coil.

How Inductor Energy Calculator Works

Magnetic energy in an inductor builds up as the current ramps from zero to its steady value, and the textbook derivation integrates the back-EMF power against the current to land on a clean closed form.

E = 1/2 × L × I²
  • E: Magnetic energy stored in the inductor, returned in joules (auto-prefixed nJ, µJ, mJ, J).
  • L: Self-inductance of the coil, taken from your input in henries after prefix conversion.
  • I: Steady current through the coil, taken from your input in amperes after prefix conversion.

The current-squared dependency means the stored magnetic energy quadruples when the current doubles, which is why a coil that looks harmless at 100 mA can still produce a small arc when its current path is suddenly opened.

When the calculator solves in reverse, it keeps the same energy variable and isolates the requested unknown. I = sqrt(2 E / L) and L = 2 E / I² follow algebraically from E = 1/2 L I² and stay consistent with the same OpenStax derivation.

Worked example: 20 µH inductor carrying 300 mA

L = 20 µH = 2 × 10⁻⁵ H, I = 300 mA = 3 × 10⁻¹ A

E = 1/2 × 2 × 10⁻⁵ H × (3 × 10⁻¹ A)² = 9 × 10⁻⁷ J

E = 9 × 10⁻⁷ J = 0.9 µJ

A small surface-mount inductor only stores sub-microwatt-seconds of energy, which is why switching supplies need fast catch diodes.

According to OpenStax University Physics Volume 2, the magnetic energy stored in any inductor is U = 1/2 L I², derived by integrating the back-EMF power L dI/dt against the current from 0 to I.

According to Wikipedia Inductor article, Wikipedia's Inductor page gives the same stored energy formula W = 1/2 L I^2 for an ideal inductor.

On the other side of an LC tank, the capacitor calculator returns the matching electric energy 1/2 C V² for the same circuit, which is why inductor energy and capacitor energy are usually solved side by side.

Key Concepts Explained

Four concepts carry the entire derivation of stored magnetic energy, and each one feeds the calculator in a different way.

Self-inductance

Self-inductance L measures how much magnetic flux a coil links for each ampere of its own current. It is measured in henries and absorbed into the E = 1/2 L I² formula, so the geometry of the coil (turns, core, area, length) does not need to be re-derived each time.

Magnetic flux linkage

When current changes, the coil resists that change by inducing a back-EMF proportional to L dI/dt. Integrating that EMF against the current gives the stored magnetic energy E = 1/2 L I², which is the same expression used in the calculator.

Current squared dependency

Magnetic energy scales with the square of current. Doubling the current quadruples the stored joules, which is why the energy readout in this calculator jumps rapidly when the current input moves up.

Ideal inductor assumption

The formula assumes an ideal inductor with no winding resistance, core loss, or stray capacitance. Real coils dissipate some supply energy as heat, so the calculator reports the field-only magnetic energy term and not the total energy drawn from the source.

These four concepts let the calculation stay a single equation. Copper losses, fringing flux, and saturation are separate corrections you add after running the calculator, not parts of the result.

Because the magnetic energy built up in an inductor is exchanged with the electric energy in a capacitor during LC oscillation, the capacitor charge time calculator helps predict how long each charge and discharge cycle takes.

How to Use This Calculator

The calculator is built around three modes. Most users leave the default and the calculator solves the stored energy directly.

  • 1 Pick what you want to solve for: Choose Stored magnetic energy for the normal forward solve, or pick Current or Inductance to reverse-engineer the coil to a target joule value.
  • 2 Enter the inductance and its prefix: Type the coil inductance, then pick H, mH, µH, or nH. The value is converted to henries internally.
  • 3 Enter the current and its prefix: Type the steady current and pick A, mA, or µA. The current is squared, so a small typo has an outsized effect on the joule result.
  • 4 Add a target energy if you picked a reverse mode: For Current or Inductance modes, type the magnetic energy to store and pick its prefix.
  • 5 Read the energy result and the supporting rows: The primary output is stored magnetic energy in joules, auto-prefixed. Supporting rows show L in henries, I in amperes, and I².
  • 6 Reset if you want to start over: Press Reset to clear inputs back to the OpenStax example (20 µH and 300 mA) so you can confirm a fresh answer.
  • Use this calculator to size a 100 µH buck inductor at 500 mA: enter 100 µH and 500 mA, leave Solve For at energy, and the calculator returns 12.5 mJ of stored magnetic energy, the joule value you would compare against the inductor's saturation rating before picking a part.

    If the inductor is part of a low-pass or high-pass filter, the capacitive reactance calculator gives the matching 1/(2π f C) value for the capacitor on the same frequency, which makes crossover and filter design easier around the inductor energy calculator.

Benefits of Using This Calculator

The calculator removes the unit-prefix gymnastics that usually come with E = 1/2 L I², so you can focus on the answer instead of the conversion.

  • Covers the full SI prefix range: Works with H, mH, µH, nH inductance and A, mA, µA current so you can type the value straight off the inductor datasheet.
  • Auto-prefixed joule output: Returns energy in the most readable unit between nJ and J so the result fits on one line for RF chokes and power chokes alike.
  • Two reverse-solve modes: Pick the coil current or inductance needed to hit a target stored energy, the practical workflow when sizing a coil for a given energy budget.
  • Shows the intermediate values: Reports L in henries, I in amperes, and I² alongside the stored energy so you can sanity-check each term in E = 1/2 L I².
  • OpenStax-aligned worked example: Comes with the 20 µH at 300 mA example from OpenStax University Physics, so students and instructors match the output to a known textbook answer.

These benefits apply whether you are sizing a switching supply inductor, checking an LC tank, or working through a homework problem, because the underlying formula is the same in every case.

Factors That Affect Your Results

Five variables move the stored magnetic energy around, and three limitations tell you where to stop trusting the result.

Coil inductance

Energy scales linearly with inductance. Doubling the henries doubles the joules stored at the same current, which is the design knob engineers use when they need more energy without raising the current.

Operating current

Energy scales with the square of current. Doubling the amperes quadruples the joules, which is also the reason a coil that is safe at low current can saturate or arc at high current.

Core material and permeability

A high-permeability core raises the inductance for the same coil geometry, so for a fixed current the stored magnetic energy rises with the core permeability.

Coil geometry and turns

More turns or a larger cross-section increase L, which raises E = 1/2 L I² at the same current, but only up to the point where the core saturates and the inductance starts to fall.

Temperature

Winding resistance and core loss both grow with temperature, so part of the supply energy leaves the magnetic field as heat instead of staying stored as magnetic energy.

  • Ideal inductor assumption: the calculator ignores copper loss, core loss, and stray capacitance, so the joule output is the field-only magnetic energy term.
  • Saturation is not modeled: real inductors lose inductance as the core approaches saturation, so the formula over-estimates stored energy near the saturation current.
  • Reverse-solve modes need both inputs: the current and inductance reverse solves still require positive target energy and a non-zero partner input, otherwise the calculator returns 0 with a hint.

For most textbook and design checks those three limitations are small enough to ignore. Near saturation or at high frequency, treat the output as the upper bound and apply a derating factor from the inductor datasheet.

In an LC tank, magnetic and electric energy swap each cycle at the resonant frequency, and the result here gives the peak joules available to charge the capacitor.

According to Omni Calculator, Omni's inductor energy storage page uses the same E = 1/2 × L × I^2 expression and the same 20 µH at 300 mA worked example.

When the inductor feeds a series stack of capacitors in a resonant network, the capacitors in series calculator gives the equivalent capacitance the inductor is exchanging energy with, which is the value used to compute the tank's resonant frequency.

Inductor energy calculator solving E = 1/2 L I^2 for any coil with H, mH, µH, nH inductance and A, mA or µA current with auto J, mJ, µJ output
Inductor energy calculator solving E = 1/2 L I^2 for any coil with H, mH, µH, nH inductance and A, mA or µA current with auto J, mJ, µJ output

Frequently Asked Questions

Q: What is the formula for the energy stored in an inductor?

A: The stored magnetic energy is E = 1/2 × L × I², where L is the inductance in henries and I is the steady current through the coil in amperes. OpenStax University Physics Volume 2 derives this directly from the back-EMF integral and uses 9 × 10⁻⁷ J as the answer for a 20 µH inductor carrying 300 mA.

Q: How do you calculate energy stored in an inductor?

A: Convert the inductance to henries and the current to amperes, then plug both into E = 1/2 × L × I². For L = 100 mH and I = 500 mA the formula gives E = 0.5 × 0.1 × 0.25 = 0.0125 J, or 12.5 mJ, which is the same value the inductor energy calculator returns in auto-prefixed mJ.

Q: Why does the energy in an inductor depend on current squared?

A: The energy comes from integrating the back-EMF, which is proportional to the current, against the current itself. That integral is linear in L and quadratic in I, which is why the stored magnetic energy grows like I² and quadruples whenever the current doubles.

Q: What happens to the energy in an inductor when the current is switched off?

A: The magnetic field collapses and tries to keep the current flowing, which produces a voltage spike across whatever switch opened the circuit. That is the source of the small arc you see when you unplug an energized coil and the reason snubber diodes are placed across relay coils and flyback inductors.

Q: How much energy is stored in a 1 mH inductor carrying 1 A?

A: Plug L = 1 mH = 1 × 10⁻³ H and I = 1 A into E = 1/2 × L × I² to get E = 0.5 × 10⁻³ × 1 = 5 × 10⁻⁴ J, or 500 µJ. A 1 mH inductor carrying 1 A is a useful reference point because it sits in the middle of the audio-frequency filter range.

Q: Does the energy in an inductor depend on the wire diameter?

A: No, the magnetic energy term E = 1/2 × L × I² does not include the wire diameter. Wire diameter only affects how much current the coil can carry before it heats up or saturates, both of which are loss mechanisms the ideal formula does not include.