Potato Calculator - Mass, Dry Matter, Water %
Use this potato calculator to enter initial mass and water % and read the new total mass, dry matter, and water evaporated after dehydration.
Potato Calculator
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What Is a Potato Calculator?
A potato calculator answers the famous potato paradox, the counter-intuitive math puzzle about how the total mass of a hydrated material changes as its water percentage changes.
- • Math class and puzzle nights: Show students and friends why 100 kg of potatoes at 99% water becomes 50 kg of potatoes at 98% water, and walk through the dry-mass identity that makes the answer click.
- • Food science and dehydration: Estimate the weight of dried potatoes, fruit leather, beef jerky, or any other food that loses water during processing, using the same dry-mass identity that anchors the paradox.
- • Reverse engineering from a target dry matter: Work backwards from a known dry matter percentage to back out the initial mass before dehydration, which is useful for storage, transport, and yield planning.
- • Sanity check for percentage and mass problems: Verify the relationship between a percentage and a raw mass in homework, lab work, or pricing problems where the answer needs to make physical sense, not just arithmetic sense.
The potato paradox was popularised in Darling's "The Universal Book of Mathematics" and survives in math education, contest problem sets, and a Car Talk puzzler, but the underlying identity is general: any hydrated material obeys the same dry-mass conservation, so the calculator works for fruit, soil, sludge, or laundry, not just potatoes.
The page is built so that you can run the paradox forward (initial mass plus starting water % plus a lower target water %) and read the surprising new total mass in real time. You can also rehydrate a sample by entering a higher target water %, and the page reports a negative water-evaporated value to show that the sample gained mass.
Because the math is short, the calculator is also useful as a teaching aid. Watching the dry mass stay fixed while the water mass and total mass change is the visual payoff of the page, and it is exactly the move that makes the 100 kg, 99% water riddle feel obvious after you see it once.
When the question is reframed as how much smaller one number is than another, the Percentage Decrease Calculator applies the same percentage-of-total thinking to any starting and ending pair of values.
How the Potato Calculator Works
The math is two short identities chained together: the dry mass never changes, and the new total mass is whatever the dry mass has to be in order to land on the requested water percentage.
- initialMass: Total mass of the hydrated material in kilograms before any dehydration happens.
- waterPercentBefore: Share of the initial total mass that is water, expressed as a percentage from 0 to 100.
- waterPercentAfter: Target share of the new total mass that is water, expressed as a percentage from 0 to 100.
Step 1: the calculator reads the initial total mass and the starting water percentage, then multiplies them to expose the dry mass. Step 2: it takes the new water percentage, flips it into a dry fraction, and divides the dry mass by that new dry fraction to recover the new total mass. Step 3: it subtracts the dry mass from the new total to give the new water mass, and subtracts the new total from the initial total to give the water evaporated.
Each of those steps is exactly the algebra that makes the classic 100 kg, 99% water riddle fall apart, and each one is reproducible by hand on a sheet of paper, so the page can be used as a worked-example generator as well as a calculator.
Classic paradox: 100 kg of potatoes at 99% water dried to 98% water
Initial mass = 100 kg, starting water = 99%, target water = 98%.
Dry mass = 100 * (1 - 99/100) = 100 * 0.01 = 1 kg. New mass = 1 / (1 - 98/100) = 1 / 0.02 = 50 kg.
New total mass = 50 kg, dry mass = 1 kg, water evaporated = 50 kg.
The 1 kg of dry matter that was 1% of 100 kg now has to be 2% of the new total, so the total has to halve. The water loss looks large because almost all of the original mass was water.
According to Wolfram MathWorld, after 100 pounds of 99%-water potatoes dehydrate to 98% water, the surprising weight is 50 pounds, because the dry mass of 1 pound is now 2% of the total.
If you need the raw mass difference in kilograms instead of the percentage, the Absolute Change Calculator gives the signed magnitude between any two numbers in the same units.
Key Concepts Behind the Potato Paradox
Four short ideas drive the math; once each one is clear, the 100 kg, 99% water riddle stops being a surprise.
Dry mass
Dry mass is the non-water portion of the sample. It does not change during dehydration, which is what lets the math solve for the new total mass from the requested water percentage alone.
Water mass
Water mass is the variable portion of the sample. It is whatever value is needed to make the total mass hit the requested water percentage, and it is what evaporates (or is added) to move between two water percentages.
Water percentage
Water percentage is water mass divided by total mass, expressed as a percentage. It is the framing of the puzzle, and the only field the user has to set in the new state to recover the new total mass.
Inverse relationship at high water %
When the starting water percentage is high, the dry fraction is small, so a one-percentage-point move in the water percentage produces a much larger move in the total mass. That is why 99% to 98% halves the total, while 50% to 49% only changes the total by about 2%.
These four concepts are enough to derive the formula on the page. They also explain why the same formula behaves dramatically differently at different water percentages, which is the source of the surprise in the original puzzle.
The relationship between the starting mass, the final mass, and the water percentage is the same signed difference that the Percentage Change Calculator measures between any two values.
How to Use the Potato Calculator
Five short steps get you from the riddle to a defensible new total mass, and the page does the algebra in the background so you can focus on the result.
- 1 Enter the initial total mass: Type the total mass of the hydrated material in kilograms. For the classic paradox, this is 100.
- 2 Enter the starting water percentage: Type the share of the initial mass that is water. For the classic paradox, this is 99%.
- 3 Read the initial dry mass and water mass: The page shows the dry mass and the water mass of the starting sample. The dry mass is the value the rest of the math anchors to.
- 4 Enter the target water percentage: Type the water percentage you want after dehydration, which can be lower (dehydration) or higher (rehydration) than the starting value.
- 5 Read the new total mass and the water evaporated: The page shows the new total mass, the new water mass, the unchanged dry mass, and the water evaporated, all in kilograms, all updated in real time as you type.
To verify the classic 100 kg, 99% to 98% riddle, type 100, 99, and 98 into the three fields. The page should show a dry mass of 1 kg, a new total mass of 50 kg, and 50 kg of water evaporated, which matches the textbook answer.
If you are working out baker's percentages in a kitchen, the Bakers Percentage Calculator covers the same percentage-to-ingredient math from a culinary angle.
Benefits of Using This Potato Calculator
The same identity that makes the paradox click is also useful for a handful of practical problems, which is why the page goes beyond a yes-or-no answer.
- • Show the paradox step by step: Walk through the dry-mass identity with students, friends, or co-workers and watch the new total mass update live as the target water percentage changes.
- • Estimate dehydrated food yields: Plan the weight of dried potatoes, fruit, herbs, or jerky from a starting fresh weight and a target final water content, and avoid surprise shortages or excess.
- • Plan harvest and storage logistics: Pre-dehydration weights feed into transport, packaging, and storage cost models, and the page gives a quick answer to how much weight is lost at the target water content.
- • Solve reverse-direction problems: Enter a higher target water percentage to rehydrate a sample, and the page reports a negative water evaporated value, which is the same identity used in reverse.
- • Sanity check percentage and mass intuitions: Catch common percentage errors where a one-point move is treated as a small change, when it is in fact a large change at high water percentages.
For a kitchen use case that depends on a fixed water ratio, the Rice to Water Ratio Calculator solves the same forward ratio problem with a different unit.
Factors That Affect the Result
Three things determine how big the surprise is, and three caveats keep the model honest when the page is used outside the original puzzle.
Starting water percentage
The closer the starting water percentage is to 100%, the smaller the dry fraction, and the more dramatically a one-point change in water percentage moves the total mass.
Step size of the water percentage change
A one-point move from 99% to 98% halves the total mass, but a one-point move from 50% to 49% only changes the total by about 2%, because the dry fraction is much larger.
Rehydration versus dehydration direction
The same identity runs in both directions, and entering a target water percentage above the starting one yields a new total mass that is larger than the initial mass and a negative water-evaporated value.
- • The math assumes a single, uniform water percentage throughout the sample, which is a fair model for a well-mixed batch of potatoes or a thin layer of drying food, but a poor model for layered or partially dried material where the surface and the centre have very different water contents.
- • The identity treats all mass loss as water, so it does not capture small amounts of volatile flavour and aroma compounds that can leave alongside water during real dehydration, and it does not model sugar or salt migration.
- • The page is a teaching and planning tool, not a lab instrument, so the result should be read as a target or a back-of-the-envelope estimate, not as a measurement of a real sample.
According to Wikipedia, the potato paradox is a veridical paradox in which 100 kg of 99%-water potatoes that dehydrate to 98% water weigh 50 kg, since the unchanged 1 kg of dry matter now has to be 2% of the total mass.
Frequently Asked Questions
Q: What is the potato paradox?
A: The potato paradox is a math puzzle in which the total mass of a hydrated material falls dramatically when its water percentage falls by a single point. The classic version asks what 100 kg of potatoes that are 99% water weigh after they dry to 98% water, and the surprising answer is 50 kg.
Q: How do I calculate the new weight of potatoes after dehydration?
A: Multiply the initial mass by the initial dry fraction (1 minus the starting water fraction) to get the dry mass, then divide the dry mass by the new dry fraction (1 minus the new water fraction). The potato calculator does both steps in real time and also reports the water evaporated.
Q: Does dehydration change the dry weight of potatoes?
A: No. Dehydration only removes water, so the dry weight of the sample does not change. The new total mass drops because water is leaving, and the new water percentage changes because the same dry weight is now a larger share of a smaller total.
Q: What is the formula for the potato paradox?
A: The formula is newMass = initialMass * (1 - waterPercentBefore / 100) / (1 - waterPercentAfter / 100). The dry mass is initialMass * (1 - waterPercentBefore / 100), and the new total mass is that dry mass divided by the new dry fraction.
Q: Why does the mass of potatoes seem to change so much with a small water percentage change?
A: At high water percentages the dry fraction is tiny, so a one-point move in the water percentage is a large relative move in the dry fraction. Going from 99% to 98% doubles the dry fraction, which forces the total mass to halve when the dry mass itself does not change.
Q: Can the potato paradox be applied to other foods?
A: Yes. Any hydrated material follows the same dry-mass identity, so the calculator works for fruit, herbs, meat jerky, soil, sludge, or laundry, as long as a single uniform water percentage is a reasonable model for the sample.