Evaporation Rate - kg per Hour Water Loss
Use this evaporation rate calculator to convert surface area, wind, and humidity into the kg of water lost per hour from a pool or pond.
Evaporation Rate
Results
What Is Evaporation Rate?
An evaporation rate calculator converts the open water surface area, the wind speed just above the water, the water and air temperatures, the relative humidity, and the local atmospheric pressure into the kilograms of water lost per hour from a pool, pond, tank, or other open water surface, using the empirical (25+19v) formula published by Engineering ToolBox. Use it whenever you need a realistic estimate of how fast water disappears from a swimming pool, irrigation reservoir, cooling pond, or garden pond.
- • Pool water loss planning: estimate how many litres per hour to top up a backyard pool during a heat wave to budget water and chemicals.
- • Pond and lake water budget: size an automatic top-up valve for a koi pond or stormwater retention pond.
- • Cooling-tower make-up: calculate how much water a cooling tower or evaporative cooler pulls out so the make-up line can be sized.
- • Industrial tank loss: predict water loss from an open process tank or quench tank so emissions drift are tracked.
The result depends on the humidity ratio the air can hold at the water surface, and the absolute humidity calculator computes the matching water vapor density in g/m^3 from the same temperature, relative humidity, and pressure inputs.
How the Calculator Works
The calculator reads six inputs, computes the saturation humidity ratio at the water temperature and the actual humidity ratio at the air temperature, multiplies their difference by theta = 25 + 19v and the surface area, and returns kilograms of water lost per hour together with the daily total, the litre and pound equivalents, the theta coefficient, and the latent heat removed.
- g_h: water loss in kilograms per hour from the open surface.
- v: air speed just above the water in metres per second.
- A: open water surface area in square metres.
- X_s: saturation humidity ratio at the water surface temperature, in kg water per kg dry air.
- X: current humidity ratio at the air temperature and relative humidity, in kg water per kg dry air.
Saturation vapor pressure uses the Tetens equation 610.78 * exp(17.27 * T / (T + 237.3)) in pascals, accurate to about 0.4 percent between 0 and 50 degrees C. The humidity ratio formula x = 0.62198 * pw / (pa - pw) converts that partial pressure into kg of water vapor per kg of dry air.
Garden pond, 20 degC, 70% RH, 5 mph breeze
A = 1.86 m^2, v = 2.22 m/s, T_water = 20 degC, T_air = 20 degC, RH = 70%, P = 101.325 kPa.
Xs = 0.01469 kg/kg, X = 0.01021 kg/kg, theta = 67.18 kg/m^2/h. g_h = 67.18 x 1.86 x 0.00448 = 0.56 kg/h.
Evaporation rate = 0.56 kg/h (1.23 lb/h); theta = 67.18; latent heat = 0.39 kW.
Matches the Omni Calculator worked example for the same 20 sq ft pond, which gives 1.2 lb/h.
According to Engineering ToolBox - Evaporation from a Water Surface, the empirical evaporation coefficient is theta = (25 + 19 v) kg/m^2/h with v in m/s, and the hourly water loss is g_h = theta * A * (Xs - X).
The (Xs - X) humidity ratio gap in this formula also drives plant transpiration, and the vapor pressure deficit calculator reports the matching saturation minus actual vapor pressure in kPa from the same temperature and humidity inputs.
Key Concepts Behind the Result
Four ideas drive the calculation. None dominates on its own, so changing one without re-checking the others can leave you surprised at how much (or how little) water actually disappears.
Humidity ratio X
Humidity ratio is the kilograms of water vapor per kilogram of dry air. Unlike relative humidity, X does not change with temperature after the air mass is sealed, which is why it is the natural variable for this formula: the air just above the water simply has to absorb a little more X to reach the new saturation value Xs.
Saturation humidity ratio Xs
Xs is the humidity ratio of air in equilibrium with a flat water surface at temperature T. It jumps from 0.00377 kg/kg at 0 degC to 0.0271 kg/kg at 30 degC, which is why warm summer air can carry seven times more water than cold winter air.
Wind-driven coefficient theta = 25 + 19v
Theta captures how wind strips the saturated air layer away from the water surface and replaces it with drier air. Still air keeps theta at 25 kg/m^2/h, a 5 m/s breeze lifts theta to 120 kg/m^2/h, and most pools and ponds sit between those two extremes.
Surface area as a linear multiplier
Doubling the open surface area doubles the loss at fixed wind, temperature, and humidity. This is why a pool cover is the most effective control: it removes the A term without touching the others, and Engineering ToolBox reports covers can cut total pool water loss by more than 90 percent.
The 0.62198 in the humidity ratio formula is just the ratio of the molar mass of water to that of dry air, and the air density calculator computes the matching density of the same moist air parcel from temperature, pressure, and relative humidity.
How to Use This Calculator
Run the calculator in six steps, then read both the kg/h number and the latent heat output so the same condition does not catch you by surprise on the energy bill.
- 1 Enter the surface area: Type the open water surface area in square metres. For a rectangular pool multiply length by width; for a circular pond use pi times radius squared.
- 2 Enter the wind speed: Use the average wind speed just above the water, not the open-field gust. A backyard anemometer or the local forecast's sustained wind work; convert mph or km/h to m/s if needed.
- 3 Enter both temperatures: Type the water surface temperature and the ambient air temperature in degrees Celsius. If you only have an air thermometer, set the water equal to the air and accept the small daytime error.
- 4 Enter the relative humidity: Type the current relative humidity as a percent from 0 to 100. Most weather apps report this directly.
- 5 Adjust the pressure if needed: Leave atmospheric pressure at 101.325 kPa for sea level. Reduce to about 90 kPa at 1000 m altitude and 80 kPa at 2000 m to keep the humidity ratio calculation accurate.
- 6 Read the kg/h and the latent heat: Use the kg/h number to size top-up flow, and the latent heat output to size the heater that has to replace what evaporation steals from the water.
If the pool or tank you are sizing is hot enough that evaporation is approaching boiling, the boiling point calculator returns the matching saturation temperature from pressure and substance so you can see how close you are to that limit.
Benefits of Using This Calculator
A clear kg/h number plus a kilowatt heat loss saves water, money, and chemistry. These are the most useful decisions the calculator supports.
- • Size the auto-fill line: Pick a float valve, solenoid, or supply pump rated to at least the peak kg/h rate so the pool or tank does not run dry during a hot dry afternoon.
- • Budget chemicals and water: Multiply the daily kg loss by the salt, chlorine, or pH buffer dose to know how much chemistry disappears with the water.
- • Quantify the heater load: Use the latent heat output as the heat the heater or chiller has to replace, usually 50 to 80 percent of the total HVAC load for an indoor pool.
- • Compare windbreaks and covers: Run the same pool with v = 2 m/s and v = 0.5 m/s, or with and without a cover, to see the dollar value of each intervention.
- • Plan seasonal top-up: Multiply the daily loss by the number of dry windy days in your climate window to estimate the litres to budget over a summer.
Evaporation is only one path for heat to leave a body of water; conduction through the walls and floor adds another, and the heat transfer conduction calculator returns the matching conduction loss in watts from material thickness and area.
Factors That Affect the Result
The rate printed by the calculator is the answer at the entered conditions. The actual rate can swing widely with weather and setup, and the most common drivers are below.
Wind speed above the surface
Wind drives the 19 v term in the theta = 25 + 19 v coefficient. A 0.5 m/s indoor breeze evaporates about 1.4 times as much water as a still room, and a 5 m/s outdoor wind evaporates 5 times as much.
Relative humidity of the air
Higher humidity shrinks the (Xs - X) gap and slows evaporation. At 90% relative humidity the rate can be one third of what it would be at 30%, and at 100% the process stops entirely until the water warms above the dew point.
Water and air temperature
Warm water lifts Xs because the saturation vapor pressure of water roughly doubles every 10 degC. A 30 degC pool in 25 degC air can evaporate more than twice as fast as a 20 degC pool in the same air.
Surface area and cover use
A cover effectively drops the open surface area toward zero. Engineering ToolBox notes that plastic blankets used outside operating hours are very effective and commonly used on pools, and the only way to retain the full surface in the formula is to enter the actual exposed area.
- • The (25 + 19 v) coefficient is an empirical fit from the Engineering ToolBox psychrometric chart and is most accurate between about 0 and 30 degC with light to moderate winds; very high winds, sub-zero air, or strong direct sunlight can push the actual rate above or below the prediction.
- • The formula assumes a flat open water surface. Falling water in a cooling tower, splashing from a fountain, or a thin film on a plate behaves more like a wet-surface model and will usually evaporate faster than this calculator predicts for the same area.
According to Wikipedia - Evaporation, evaporation rate is controlled by concentration of the evaporating substance in the surrounding gas, flow rate of fresh air, surface area, water temperature, and atmospheric pressure.
If the body of water holds dissolved salts or glycol, the saturation vapor pressure drops and so does the rate, and the boiling point elevation calculator shows the matching temperature shift you have to add on top of the water temperature.
Frequently Asked Questions
Q: What is the evaporation rate of water?
A: It is the mass of water that leaves an open surface per unit of time, usually expressed in kilograms per hour or pounds per hour. The Engineering ToolBox formula combines surface area, wind speed, and the humidity ratio gap between saturated air and the current air to return a single kg/h number, which works for pools, ponds, and open tanks between 0 and 30 degC.
Q: How do you calculate evaporation rate from surface area and wind?
A: Multiply the surface area by the coefficient theta = 25 + 19 v, where v is wind speed in m/s, then multiply by the humidity ratio gap Xs - X in kg water per kg dry air. For a 1.86 m^2 pond with a 2.22 m/s breeze and 70% relative humidity at 20 degC the formula gives about 0.56 kg/h of water lost, matching the Omni Calculator worked example.
Q: How does relative humidity affect evaporation rate?
A: Relative humidity shrinks the gap between Xs and X that drives evaporation. At 100% relative humidity X equals Xs and the rate drops to zero, while at 30% the gap is roughly three times larger than at 70%, so the same pool can lose more than three times as much water in dry desert air as in humid coastal air at the same temperature.
Q: How fast does pool water evaporate per hour?
A: A 30 by 15 ft (41.8 m^2) pool in 82 degF (27.8 degC) air at 80% relative humidity with a 3 mph (1.34 m/s) breeze loses about 10.35 kg/h, or 22.8 lb/h, of water. Over a six-hour afternoon that is roughly 62 kg, or about 16 US gallons, that has to be topped up to keep the level steady.
Q: What is the formula for daily evaporation rate?
A: Daily water loss is simply the hourly rate multiplied by 24, using the average wind speed, water and air temperature, and relative humidity for the day. The Engineering ToolBox formula g_h = (25 + 19 v) * A * (Xs - X) gives the kg/h number, and the calculator returns the kg/day equivalent in the secondary output row.
Q: How do you convert evaporation rate to kg per hour?
A: Use the Engineering ToolBox empirical formula g_h = (25 + 19 v) * A * (Xs - X). Convert the wind speed to m/s, the area to m^2, and the humidity ratio to kg water per kg dry air using x = 0.62198 * pw / (pa - pw). The product is already in kg/h, and dividing by 3600 turns it into kg/s for latent heat calculations.